Algebra Using Fractions
Introduction :
A fraction (from the Latin fractus, broken) is a number that can represent part of a whole. The earliest fractions were reciprocals of integers: ancient symbols representing one part of two, one part of three, one part of four, and so on. A much later development were the common or "vulgar" fractions which are still used today (½, ⅝, ¾, etc.) and which consist of a numerator and a denominator.
Source – Wikipedia.
Algebra Using Fractions in Addition:
The examples show the algebra fractions for using in addition.
= `(2x)/12` +`(4x)/12`
= `(2x+4x)/12`
= `(6x)/12`
= `(3x)/4`
Denominators are different in the given fractions.
The LCM for the denominators are
LCM of 3, 5 = 15
So `(2x*3)/(3*5)` = `(6x)/15`
`(4x*5)/(5*3)` = `(20x)/15`
Denominators are equal. To add the numerator in them.
=` (6x)/15 ` + `(20x)/15`
= `(6x+20x)/15`
= `(26x)/15` is the solution for the algebra fractions.
Denominators are different in the given fractions.
The LCM for the denominators are
LCM of 5, 2 = 10
So `(4x*5)/(5*2)` = `(20x)/10`
`(3x*2)/(2*5)` = `(6x)/10`
Denominators are equal. To add the numerator in them.
= ` (20x)/10 ` +` (6x)/10`
= `(20x+6x)/10`
= `(26x)/10` is the solution for the algebra fractions.
Algebra Using Fractions in Subtraction:
The examples show the algebra fractions for using in subtraction.
= `(2x)/12` - `(4x)/12`
= `(2x-4x)/12`
= `(-2x)/12`
= `-x/6`
Denominators are different in the given fractions.
The LCM for the denominators are
The LCM of 3, 5 = 15
So `(2x*3)/(3*5)` = `(6x)/15`
`(4x*5)/(5*3)` = `(20x)/15`
Denominators are equal. To subtract the numerator in them.
= `(6x)/15` - `(20x)/15`
= `(6x-20x)/15`
= `(-14x)/15` is the solution for the algebraic fractions.
Denominators are different in the given fractions.
The LCM for the denominators are
The LCM of 5, 2 = 10
So `(4x* 5)/(5*2)` = `(20x)/10`
`(3x*2)/(2*5) ` = ` (6x)/10`
Denominators are equal. To subtract the numerator in them.
= `(20x)/10` - `(6x)/10`
= `(20x-6x)/10`
= `(14x)/10` is the solution for the algebra fractions.
I like to share this Basic Fractions with you all through my blog.
A fraction (from the Latin fractus, broken) is a number that can represent part of a whole. The earliest fractions were reciprocals of integers: ancient symbols representing one part of two, one part of three, one part of four, and so on. A much later development were the common or "vulgar" fractions which are still used today (½, ⅝, ¾, etc.) and which consist of a numerator and a denominator.
Source – Wikipedia.
Algebra Using Fractions in Addition:
The examples show the algebra fractions for using in addition.
- Add the algebra fractions: `(2x)/12` + `(4x)/12` .
= `(2x)/12` +`(4x)/12`
= `(2x+4x)/12`
= `(6x)/12`
= `(3x)/4`
- Add the algebra fractions: `(2x)/3` + `(4x)/5`
Denominators are different in the given fractions.
The LCM for the denominators are
LCM of 3, 5 = 15
So `(2x*3)/(3*5)` = `(6x)/15`
`(4x*5)/(5*3)` = `(20x)/15`
Denominators are equal. To add the numerator in them.
=` (6x)/15 ` + `(20x)/15`
= `(6x+20x)/15`
= `(26x)/15` is the solution for the algebra fractions.
- Add the algebra fractions: `(4x)/5 ` + `(3x)/2`
Denominators are different in the given fractions.
The LCM for the denominators are
LCM of 5, 2 = 10
So `(4x*5)/(5*2)` = `(20x)/10`
`(3x*2)/(2*5)` = `(6x)/10`
Denominators are equal. To add the numerator in them.
= ` (20x)/10 ` +` (6x)/10`
= `(20x+6x)/10`
= `(26x)/10` is the solution for the algebra fractions.
Algebra Using Fractions in Subtraction:
The examples show the algebra fractions for using in subtraction.
- Subtract the algebra fractions:` (2x)/12` - `(4x)/12` .
= `(2x)/12` - `(4x)/12`
= `(2x-4x)/12`
= `(-2x)/12`
= `-x/6`
- Subtract the algebra fractions: `(2x)/3` - `(4x)/5`
Denominators are different in the given fractions.
The LCM for the denominators are
The LCM of 3, 5 = 15
So `(2x*3)/(3*5)` = `(6x)/15`
`(4x*5)/(5*3)` = `(20x)/15`
Denominators are equal. To subtract the numerator in them.
= `(6x)/15` - `(20x)/15`
= `(6x-20x)/15`
= `(-14x)/15` is the solution for the algebraic fractions.
- Subtract the fractions: `(4x)/5 ` - `(3x)/2`
Denominators are different in the given fractions.
The LCM for the denominators are
The LCM of 5, 2 = 10
So `(4x* 5)/(5*2)` = `(20x)/10`
`(3x*2)/(2*5) ` = ` (6x)/10`
Denominators are equal. To subtract the numerator in them.
= `(20x)/10` - `(6x)/10`
= `(20x-6x)/10`
= `(14x)/10` is the solution for the algebra fractions.
I like to share this Basic Fractions with you all through my blog.