Algebra 2 Problem 1
Introduction :
Algebra is the branch of mathematics concerning the study of the rules of operations and relations, and the constructions and concepts arising from them, including terms, polynomials, equations and algebraic structures. Together with geometry, analysis, topology, combinatorics, and number theory, algebra is one of the main branches of pure mathematics (source: Wikipedia).
Algebra 2 Problem 1:
Algebra 2 Answers
Multiply (3AB + 2A)(A^2 + 2AB^2). Simplify the answer.
Sol: Multiply the first terms of each bi-nomial.
3AB * A2 = 3A3B
Multiply the outside terms of each bi-nomial.
3AB * 2AB2 = 6A2B3
Multiply the inside terms of each bi-nomial.
2A * A2 = 2A3
Multiply the last terms of each bi-nomial.
2A * 2AB2 = 4A2B2
Now we have a polynomial with four terms. Combine selective terms if you can to get a simplified answer. There are no like terms, so you have to finalize the answer.
3A3B + 6A2B3 + 2A3 + 4A2B2
Therefore the final multiplied value 3A3B + 6A2B3 + 2A3 + 4A2B2
Algebra 2 Problem 2:
Multiply (X + Y)3 out.
Sol: Rewrite the value so you have something you can actually multiply out.
(X + Y)(X + Y)(X + Y)
Multiply the first two binomials together.
(X + Y)(X + Y)
X2 + XY + YX + Y2
After combining like terms, you have
X2 + 2XY + Y2
now You have a binomial and trinomial to multiply together.
(X2 + 2XY + Y2)(X + Y)
In this step slightly more complicated situation while multiplying a binomial by another binomial. So we are multiplying the first term and the trinomial then we are multiplying the last term with binomial of each term in the trinomials are shown below as like the equation.
X3 + 2X2Y + XY2 + YX2 + 2XY2 + Y3
Combine like terms if possible to simplify the answer.
X3 + 3X2Y + 3XY2 + Y3
Therefore the final multiplied value X3 + 3X2Y + 3XY2 + Y3
Algebra is the branch of mathematics concerning the study of the rules of operations and relations, and the constructions and concepts arising from them, including terms, polynomials, equations and algebraic structures. Together with geometry, analysis, topology, combinatorics, and number theory, algebra is one of the main branches of pure mathematics (source: Wikipedia).
Algebra 2 Problem 1:
Algebra 2 Answers
Multiply (3AB + 2A)(A^2 + 2AB^2). Simplify the answer.
Sol: Multiply the first terms of each bi-nomial.
3AB * A2 = 3A3B
Multiply the outside terms of each bi-nomial.
3AB * 2AB2 = 6A2B3
Multiply the inside terms of each bi-nomial.
2A * A2 = 2A3
Multiply the last terms of each bi-nomial.
2A * 2AB2 = 4A2B2
Now we have a polynomial with four terms. Combine selective terms if you can to get a simplified answer. There are no like terms, so you have to finalize the answer.
3A3B + 6A2B3 + 2A3 + 4A2B2
Therefore the final multiplied value 3A3B + 6A2B3 + 2A3 + 4A2B2
Algebra 2 Problem 2:
Multiply (X + Y)3 out.
Sol: Rewrite the value so you have something you can actually multiply out.
(X + Y)(X + Y)(X + Y)
Multiply the first two binomials together.
(X + Y)(X + Y)
X2 + XY + YX + Y2
After combining like terms, you have
X2 + 2XY + Y2
now You have a binomial and trinomial to multiply together.
(X2 + 2XY + Y2)(X + Y)
In this step slightly more complicated situation while multiplying a binomial by another binomial. So we are multiplying the first term and the trinomial then we are multiplying the last term with binomial of each term in the trinomials are shown below as like the equation.
X3 + 2X2Y + XY2 + YX2 + 2XY2 + Y3
Combine like terms if possible to simplify the answer.
X3 + 3X2Y + 3XY2 + Y3
Therefore the final multiplied value X3 + 3X2Y + 3XY2 + Y3