Algebra 1 textbook online
Introduction:
Algebra is a branch of mathematics. Algebra plays an important role in our day to day life. The algebra 1 textbook online covers the four basic operations such as addition, subtraction, multiplication and division. The most important terms of algebra 1 textbook online are variables, constant, coefficients, exponents, terms and expressions. In Algebra, besides numerals we use symbols and alphabets in place of unknown numbers to make a statement. Hence, algebra 1 textbook online may be regarded as an extension of Arithmetic.
Basic term involving algebra 1 text book online:
Variables
Algebraic variables are the alphabetical characters which are used for assigning the value. While solving the algebraic equation value of the variable will be changed. Widely used variables are x, y, z
Constant
Algebraic constants are the value whose value never changes while solving the algebraic equation. In 3y+2, the value 2 is the constant.
Term
Terms of the algebraic expressions are joined to form the algebraic expression by the arithmetic operations such as addition, subtraction, multiplication and division. In the following example 5n2 + 4n the terms 5n2, 4n are combined to form the algebraic expression 5n2 + 4n by the addition operation (+)
Order of the operation in algebra 1 textbook online:
Step 1: we have to reduce the expression within the parentheses,
Step 2: we have to reduce thel exponential expressions,
Step 3: we have to reduce multiplication or division operations,
Step 4: Finally, we have to reduce addition or subtraction operations.
Procedure for solving algebraic equation
Step 1: If we want to solve the equation for x, we have to move the x to on side of the equal sign, which is similar to, 2x+2+8=50
Step 2: Do the 'reverse operations.' This means we would want to add -8. So we will get 2x+2=42.
Step 3: Now we have to add -2 on both sides of the equation. So we will get 2x=40.
Step 4: Now we have to divide both sided by 2. That is 2x/5=40/2. Therefore, x=20.
Example problems on algebra 1 textbook online:
Example 1:
Elimination method:
x+y=9
x-y=1
x+y=9 ---------------------- equation 1
x-y=1---------------------- equation 2
Add equation 1 with equation 2
2x=10
2x/2=10/2 (both sides are divided by 2 )
x=5
Substitute x=5 in the equation 1, so we will get
5+y=9
5-5+y=9-5 ( -5 is added on both sides)
y=4
Substitution method:
x + y = 9 ---------------------- equation 1
x – y = 0---------------------- equation 2
take the equation 1
x+y=9
x+y-y=9-y (-y is added on the both sides )
x=9-y
substitute x=9-y in the equation 2, we will get
9-y – y = 0
9 - 2y = 0 (add -9 on both sides)
9 - 9- 2y = 0 - 9
-2y = -9 (divide both sides by -2)
-2y / -2 = -9 / -2
Y=4.5
Substitute y=4.5 in the equation 1
X+4.5=9
X+4.5-4.5=9-4.5 ( Add -4.5 on the both sides)
X=4.5
Example 2:
Solve for the variable x, 2x+7=25
Solution
2x+7=25
2x+7-7=25 -7(Add -7 on both sides)
2x = 18
2x/2=18/2(both sides divided by 2)
x=9
Example 3:
Simplify the expression 2*(22÷2)+x=0
Solution:
2*(22÷2) +x=0 (evaluate the expression inside the parenthesis)
2*(11) +x=0
22+x=0
22-22+x=0-22 (add -22 on both sides)
X=-22
Algebra is a branch of mathematics. Algebra plays an important role in our day to day life. The algebra 1 textbook online covers the four basic operations such as addition, subtraction, multiplication and division. The most important terms of algebra 1 textbook online are variables, constant, coefficients, exponents, terms and expressions. In Algebra, besides numerals we use symbols and alphabets in place of unknown numbers to make a statement. Hence, algebra 1 textbook online may be regarded as an extension of Arithmetic.
Basic term involving algebra 1 text book online:
Variables
Algebraic variables are the alphabetical characters which are used for assigning the value. While solving the algebraic equation value of the variable will be changed. Widely used variables are x, y, z
Constant
Algebraic constants are the value whose value never changes while solving the algebraic equation. In 3y+2, the value 2 is the constant.
Term
Terms of the algebraic expressions are joined to form the algebraic expression by the arithmetic operations such as addition, subtraction, multiplication and division. In the following example 5n2 + 4n the terms 5n2, 4n are combined to form the algebraic expression 5n2 + 4n by the addition operation (+)
Order of the operation in algebra 1 textbook online:
Step 1: we have to reduce the expression within the parentheses,
Step 2: we have to reduce thel exponential expressions,
Step 3: we have to reduce multiplication or division operations,
Step 4: Finally, we have to reduce addition or subtraction operations.
Procedure for solving algebraic equation
Step 1: If we want to solve the equation for x, we have to move the x to on side of the equal sign, which is similar to, 2x+2+8=50
Step 2: Do the 'reverse operations.' This means we would want to add -8. So we will get 2x+2=42.
Step 3: Now we have to add -2 on both sides of the equation. So we will get 2x=40.
Step 4: Now we have to divide both sided by 2. That is 2x/5=40/2. Therefore, x=20.
Example problems on algebra 1 textbook online:
Example 1:
Elimination method:
x+y=9
x-y=1
x+y=9 ---------------------- equation 1
x-y=1---------------------- equation 2
Add equation 1 with equation 2
2x=10
2x/2=10/2 (both sides are divided by 2 )
x=5
Substitute x=5 in the equation 1, so we will get
5+y=9
5-5+y=9-5 ( -5 is added on both sides)
y=4
Substitution method:
x + y = 9 ---------------------- equation 1
x – y = 0---------------------- equation 2
take the equation 1
x+y=9
x+y-y=9-y (-y is added on the both sides )
x=9-y
substitute x=9-y in the equation 2, we will get
9-y – y = 0
9 - 2y = 0 (add -9 on both sides)
9 - 9- 2y = 0 - 9
-2y = -9 (divide both sides by -2)
-2y / -2 = -9 / -2
Y=4.5
Substitute y=4.5 in the equation 1
X+4.5=9
X+4.5-4.5=9-4.5 ( Add -4.5 on the both sides)
X=4.5
Example 2:
Solve for the variable x, 2x+7=25
Solution
2x+7=25
2x+7-7=25 -7(Add -7 on both sides)
2x = 18
2x/2=18/2(both sides divided by 2)
x=9
Example 3:
Simplify the expression 2*(22÷2)+x=0
Solution:
2*(22÷2) +x=0 (evaluate the expression inside the parenthesis)
2*(11) +x=0
22+x=0
22-22+x=0-22 (add -22 on both sides)
X=-22